题目
5.化简:-|||-(1)(AB∪C)(AC);-|||-(2) (Acup B)(Acup overline (B)).
题目解答
答案
题思路：(1)原式=$\overline {AB\cup CC}\cup \overline {AC}=A\overline {B}\cup \overline {AC}=A\overline {B}\cup \overline {A}C=A\overline {B}C$
(2)原式=(A∪B)A∪(A∪B)B=A∪B
(1)A\overline {B}C$
(2)A∪B
(2)原式=(A∪B)A∪(A∪B)B=A∪B
(1)A\overline {B}C$
(2)A∪B